7 +- [2(x+1) - 3(x-2/3)]

7 +- (2x + 2 - 3x + 2)

7 +- (2x -3x + 2 + 2)

7 +- (4-x)

Two possibilities:

7 + (4-x) = 11 - x

7 - (4-x) = 7 -4 + x = 3 +x

11-x and 3+x

how do i simplify this?

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7 +- [2(x+1) - 3(x-2/3)]

7 +- (2x + 2 - 3x + 2)

7 +- (2x -3x + 2 + 2)

7 +- (4-x)

Two possibilities:

7 + (4-x) = 11 - x

7 - (4-x) = 7 -4 + x = 3 +x

11-x and 3+x

Rick B. | Most types of MathMost types of Math

You have to work from the innermost parenthesis first, so you have to distribute the '3' to the contents of its parenthesis by multiplication: 3(x-2/3) =
3x - 2

then do the same with 2(x+1): 2x + 2

Substitute the distributed values above into their spots in their original equations:

7 ± [2x+2-(3x-2)] or 7 ± [2x + 2 - (3x - 2)] = 7 ± [2x +2 - 3x + 2]

Solve for the part enclosed by parenthesis (re-write): 2x-3x +2 +2 =
-x + 4

Substitute that answer again: 7 ±[ -x + 4] and get the answers:

7+(-x+4) = **-x+11 **

and

7-(-x+4) = 7+x-4 = **x + 3**

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