the sum of two number is 50.the second number is 8 more than the first number

Question

solve algebraic equations 

 

Answer 1

Let the first number be x. Then:

the second number becomes x+8.

Set up an equation: x+(x+8)=50 => 2x+8=50 => 2x=42 => x=21 => this is the first number (because this is what we set equal to x)

Second number = x+8 => 21+8=29

Answer 2

Two unknowns x and y.

 

Using information from the problem

 

x + y = 50  Sum of two numbers is 50

y = x + 8  The second number is 8 more than the first number.

 

Replace y in first equation

 

x + (x+8) = 50

Combine x's

 

2x + 8 = 50

subtract 8 from both sides

 

2x = 42

Divide both sides by 2

 

x = 21

 

Solve for y

 

y = 21 + 8 = 29

 

The two numbers are 21 and 29.

 

 

Answer 3

Hi Nazel;

FIRST...x

SECOND...x+8

(x)+(x+8)=50

x+x+8=50

2x+8=50

Let's subtract 8 from both sides...

-8+2x+8=50-8

2x=42

Let's divide both sides by 2...

(2x)/2=42/2

x=21

FIRST...21

SECOND...21+8=29

21+29=50