solve algebraic equations

Tutors, sign in to answer this question.

Alexandra K. | UT Southwestern tutor for Math and ScienceUT Southwestern tutor for Math and Scien...

Let the first number be x. Then:

the second number becomes x+8.

Set up an equation: x+(x+8)=50 => 2x+8=50 => 2x=42 => x=21 => this is the first number (because this is what we set equal to x)

Second number = x+8 => 21+8=29

Two unknowns x and y.

Using information from the problem

x + y = 50 Sum of two numbers is 50

y = x + 8 The second number is 8 more than the first number.

Replace y in first equation

x + (x+8) = 50

Combine x's

2x + 8 = 50

subtract 8 from both sides

2x = 42

Divide both sides by 2

x = 21

Solve for y

y = 21 + 8 = 29

The two numbers are 21 and 29.

Hi Nazel;

FIRST...x

SECOND...x+8

(x)+(x+8)=50

x+x+8=50

2x+8=50

Let's subtract 8 from both sides...

-8+2x+8=50-8

2x=42

Let's divide both sides by 2...

(2x)/2=42/2

x=21

FIRST...21

SECOND...21+8=29

21+29=50

Already have an account? Log in

By signing up, I agree to Wyzant’s terms of use and privacy policy.

Or

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Your Facebook email address is associated with a Wyzant tutor account. Please use a different email address to create a new student account.

Good news! It looks like you already have an account registered with the email address **you provided**.

It looks like this is your first time here. Welcome!

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Please try again, our system had a problem processing your request.