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# the sum of two number is 50.the second number is 8 more than the first number

solve algebraic equations

### 3 Answers by Expert Tutors

Alexandra K. | UT Southwestern tutor for Math and ScienceUT Southwestern tutor for Math and Scien...
2
Let the first number be x. Then:
the second number becomes x+8.
Set up an equation: x+(x+8)=50 => 2x+8=50 => 2x=42 => x=21 => this is the first number (because this is what we set equal to x)
Second number = x+8 => 21+8=29
Susan L. | Tutor in Math and Science--Patient, Proficient, OrganizedTutor in Math and Science--Patient, Prof...
5.0 5.0 (11 lesson ratings) (11)
1
Two unknowns x and y.

Using information from the problem

x + y = 50  Sum of two numbers is 50
y = x + 8  The second number is 8 more than the first number.

Replace y in first equation

x + (x+8) = 50
Combine x's

2x + 8 = 50
subtract 8 from both sides

2x = 42
Divide both sides by 2

x = 21

Solve for y

y = 21 + 8 = 29

The two numbers are 21 and 29.

Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
-1
Hi Nazel;
FIRST...x
SECOND...x+8
(x)+(x+8)=50
x+x+8=50
2x+8=50
Let's subtract 8 from both sides...
-8+2x+8=50-8
2x=42
Let's divide both sides by 2...
(2x)/2=42/2
x=21
FIRST...21
SECOND...21+8=29
21+29=50