how to find this equation in intercept form (-2,4)and(3,-1)

Question

how to find this equation in intercept form (-2,4)and(3,-1)

Answer 1

Line equation in intercept form: x/a + y/b = 1, where a is the x-intercept, and b is the y-intercept of the line.

slope m = (4+1)/(-2-3) = -1 = -b/a

So, x+y = constant

Plug in (-2, 4),

x+y = -2+4 = 2

 

Answer: x/2 + y/2 = 1

Answer 2

Once you found the value of the slope, it's better to use point-slope form of linear equation for this kind of problems.

(y - y₁) = m(x - x₁)

y - 4 = -1[x - (-2)]  

y = -1(x + 2) + 4

y = - x - 2 + 4

y = - x + 2

Answer 3

Hi Jala;

(-2,4) and (3,-1)

Let's establish slope.

m=(y-y₁)/(x-x₁)

m=(4--1)/(-2-3)

Subtracting a negative number is the same as adding a positive number...

m=(4+1)/(-2-3)

m=5/-5=-1

y=-1x+b

y=-x+b

y=mx+b is the slope-intercept formula.  Slope is represented by m, and the y-intercept, the value of y when x=0, is represented by b.

y=-x+b

Let's plug in one set of coordinates..

4=-(-2)+b

4=2+b

Let's subtract 2 from both sides...

4-2=2+b-2

2=b

y=-x+2

 

Let's check our work using the other set of coordinates...

-1=-(3)+2

-1=-3+2

-1=-1