Find the exact value if sin x= -5/13, cos y= 4/5, 3pi/2<x<2pi, and 3pi/2<y<2pi what is tan(x+y)

Question

I am a little confused on this and it would be nice if someone could work through it so I can understand this problem

Answer 1

X is in forth quadrant, so, tan (x)  will be negative

 

Tan(x)=-5/12

 

Y is in forth quadrant , so, tan(y) will be negative

 

Tan(y)=-3/4

 

Tan(x+y)= (tan(x)+tan(y))/(1-tan(x)tan(y)

 

plug in the values yourself