
Andrew M. answered 03/11/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
A person invests $2860 for 15 years in an account that earns 4.6% annual interest.
The way your question is phrased the interest would be compounded
once per year. Based on the questions you are asked to solve, I will
assume the world "annually" should not be in the above sentence.
Your problem utilizes the compound interest formula:
A = p(1+r/n)nt
A = future amount
p = principal or initial investment = 2860
r = interest rate as decimal = .046
n = number of times compounded each year
t = time in years = 15
1. Semiannually means interest compounded 2 times yearly so n=2
A = 2860(1+.046/2)2(15) = 2860(1.023)30 = 5657.64
Annually means interest compounded 1 time yearly so n=1
A = 2860(1+.046/1)1(15) = 2860(1.046)15 = 5614.89
The difference is 5657.64 - 5614.89 = $42.75 with semiannually
being the larger interest earned.
2. Quarterly: Interest compounded 4 times per year, n=4
A = 2860(1+.046/4)4(15)
Semiannually: Refer to problem 1: A = 5657.64
Work the quarterly formula on calculator and find the difference.
3. Monthly: Interest compounded 12 times per year, n=12
A = 2860(1 + .046/12)12(15)
Quarterly: Refer to problem 2 for quarterly final amount.
4. Daily: Interest compounded 365 times per year, n=365
A = 2860(1 + .046/365)365(15)
Monthly: Refer to problem 3 for monthly final amount.
5. Interest compounded continually uses a different formula.
A = Pert
e is Eulers number... approximately 2.7183... find it on calculator
A = 2860e.046(15)
A = $5702.03
For daily compounding amount refer to problem 4.