David W. answered 02/27/16
Experienced Prof
More detail of the problem statement: When the line with equation (y=5x+10) is graphed, it crosses the point (a,2) [which is in (x,y) form, remember?]. That means that x=a and y=5 on the plot (graph).
The variables x and y are used to represent any point on those axes. Constants like 2 and 10 represent known numerical values. Letters like "a" are constants (not variables) with a singe unknown value.
This problem asks you to find the value of the constant "a" for which the point (a,2) is on the line (y=5x+10).
For both of these conditions to be true, we must have:
2 = 5(a) + 10 [insert x=a and y=2]
Now, we can use the rules of algebra to isolate "a" and determine its value.
Solution:
2 = 5a + 10 [re-write]
-8 = 5a [subtract 10 from both sides because 10 had been added]
-8/5 = a [divide both sides by 5
because "a" had been multiplied by 5]
The value of a is (-8/5).
Checking (very important):
Is point (-8/5,2) on the line (y=5x+10) ?
2 = 5(-8/5) + 10 ?
2 = -8 + 10 ?
2 = 2 ?yes
David W.
02/27/16