Raymond B. answered 02/16/26
Math, microeconomics or criminal justice
80% of 700 = 560
you could use a binomial to approximate the normal, as there are two events, either text or not
mean = np = .80 x 700 = 560
var = npq = 560 x .2 = 112
sd = sqrVar = sqr112 = 10.583
z score for 555 = (555- 560)/sqr112 = about -0.4724555913
use z tables to find the area under the normal curve
= the probability
= .3183= 31.83% = p(x<z)
.3336 is approximately .3183