specific heat problem

Question

A 23.06 g sample of a substance is initially at 27.6 °C. After absorbing 2511 J of heat, the temperature of the substance is 178.2 °C. What is the specific heat (SH) of the substance?

Answer 1

Hi Beatrice,

Quantity of heat = mass of substancesXspecific heatXtemperature difference

         Q             =  M XSHXΔT

Q = 2511 J, ΔT = 178.2°C - 27.6°C=150.6°C, M = 23.06 g(1kg/1000 g)=0.02306 kg

 

2511 J = (0.02306 kg)XSHX(150.6 °C)

SH = 2511 J /(3.4728 kg °C)

The specific heat of the substance is 723 J/kg·°C