in a parallelogram ABCD ,it is being given that AB=10 CM qnd the altitudes corresponding to the sides AB and AD are DL=6 CM AND BM= 8 cm respectively find AD

Question

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Answer 1

Let the area from the triangle formed from side AB=area formed from triangle formed from side AD.

 

Area formed from AB's triangle: (1/2)*6 cm*10 cm  (Area of triangle is one-half bas times height).

 

Area=30 square cm

 

Solve for side AD

 

30=(1/2)*8 cm*AD

 

30=4*AD

 

30/4=AD or AD=7.5 cm