Question is in description.

Question

Find the equation for the line that passes through the point (2, −3), and that is perpendicular to the line with the equation x − 3y = 3.

Answer 1

x-3y = 3

-3y =-x +3

y = x/3 -1, slope = 1/3

for a perpendicular line, the slope is the negative inverse, or -3

y=-3x +b to solve for b plug in the point

-3 =-3(2) + b

b = -3+6 = 3

y=-3x+3 is the perpendicular line through the given point