Question is in description.

Question

Find the equation for the line that passes through the point (1, 5), and that is perpendicular to the line with the equation 2x − 3y = 11

Answer 1

2x-3y = 11

-3y = -2x + 11

y = (2/3)x -11/3

slope = 2/3, for a line perpendicular the slope is the negative inverse = -3/2

y =-(3/2)x + b. plug in the point (1,5) y=5, x=1 to solve for b

5=-(3/2)(1) + b

b = 5 + 3/2 = 13/2

y = (-3/2)x + 13/2 is the perpendicular equation for the line passing through (1,5)