Let A = number of adult tickets, and C = number of child tickets
Then A + C = 600 tickets; A = 600 - C
Then $9 x A + $6 x C = $4260
Then $9 (600 - C) + $6C = $4260, which becomes $5400 - $9C + $6C = $4260
Combining, we get $5400 - $9C + $6C = $4260
Rearranging, we get $5400 - $4260 = $3C
Then, $1140 = $3C, which becomes 380 = C
Then, the number of adult tickets is 600 - 380 = 220
Proof: 220 tickets x $9/Adult + 380 tickets x $3/child = $4260