Arthur D. answered 01/23/16
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7+√3x=√(5x+4)+5
7-5=√(5x+4)-√3x
2=√(5x+4)-√3x
square both sides
4=(5x+4)-2√(3x(5x+4))+3x
4=8x+4-2√(15x2+12x)
4-4=8x-2√(15x2+12x)
0=8x-2√(15x2+12x)
-8x=-2√(15x2+12x)
divide both sides by -2
4x=√(15x2+12x)
square both sides
16x2=15x2+12x
16x2-15x2-12x=0
x2-12x=0
factor
x(x-12)=0
x=0
x-12=0
x=12
there are two solutions: x=0 and x=12