Solve using quadratic formula

Question

x²=4/5x-6/25

Answer 1

Let's restate the equation you have

x² = (4/5)x - (6/25)

 

to

x² - (4/5)x + (6/25) = 0

 

The quadratic formula is

-b ± √(b²-4ac)

-----------------  where a=1, b=-4/5 and c=6/25 

        2a

 

-(-4/5) ±√[(-4/5)²-(4)(1)(6/25)]

-------------------------------------

                 (2)(1)

 

4/5 ±√[(16/25)-(24/25)]

-----------------------------

               2

 

4/5 ±√(-8/25)

----------------

       2

 

4/5 ±(2i√2)/5

---------------

       2

 

2/5 ± i√2/5 = 2 ±(√2)i

                     --------

                         5

 

So we have two imaginary solutions.