3/x+3 = 12x + 19/x^2 +7x+12 = 5/x+4 =

Question

Solve each equation and check for solution

Answer 1

Hey Dawn,

 I'm going to assume the equation you are trying to solve is:

 

(3/(x+3)) - ((12x+19)/(x²+7x+12)) - ((5/(x+4)) =0

 

Notice that the quadratic factors into (x+4)(x+3) now using this as a common denominator gives"

 

3(x+4)-(12x+19)-5(x+3)/((x+4)(x+3)) = 0  expanding the numerator and collecting like terms gives

 

14x+22 = 0

 

so x=-22/14 or -11/7 and this satisfies the original equation

 

Regards

Jim

Answer 2

Dawn,

 

I'm sorry

 

Am I supposed to interpret the first term as

 

(3/x) + 3 or 3/(x + 3)?

 

How about the third term

 

(5/x) + 4 or 5/(x + 4)?