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3/x+3 = 12x + 19/x^2 +7x+12 = 5/x+4 =

Solve each equation and check for solution

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Jim S. | Physics (and math) are fun, reallyPhysics (and math) are fun, really
4.7 4.7 (184 lesson ratings) (184)
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Hey Dawn,
 I'm going to assume the equation you are trying to solve is:
 
(3/(x+3)) - ((12x+19)/(x2+7x+12)) - ((5/(x+4)) =0
 
Notice that the quadratic factors into (x+4)(x+3) now using this as a common denominator gives"
 
3(x+4)-(12x+19)-5(x+3)/((x+4)(x+3)) = 0  expanding the numerator and collecting like terms gives
 
14x+22 = 0
 
so x=-22/14 or -11/7 and this satisfies the original equation
 
Regards
Jim
William S. | Experienced scientist, mathematician and instructor - WilliamExperienced scientist, mathematician and...
4.4 4.4 (10 lesson ratings) (10)
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Dawn,
 
I'm sorry
 
Am I supposed to interpret the first term as
 
(3/x) + 3 or 3/(x + 3)?
 
How about the third term
 
(5/x) + 4 or 5/(x + 4)?