Using chain rule and product/quotient rule, find derivative of sin(3x^2)/x when x=(squareroot of pi)

Question

sin(3x^2)x^-1

 

this is how far I got.  when do I sub in √pi ?

what do I do next?

Answer 1

y = sin(3x²)x^-1

 

y' = sin(3x²)(-x^-2) + x^-1cos(3x²)(6x)

 

   = -sin(3x²)/x² +6cos(3x²)

Answer 2

sin(3x^2)x^-1 = sin (3x^2).-x^-2 + 6x cos(3x^2).x^-1 = -sin (3x^2)/x^2 + 6 cos (3x^2)