im needing help with algebra

Question

how would you factor:

6x^2-x-2

x^2-3x+2x-6

81y^2-36

Answer 1

 

 

6x^2-x-2 = (3x-2)(2x+1), inverse foil

x^2-3x+2x-6 = x(x-3) + 2(x-3) = (x+2)(x-3), by grouping

81y^2-36 = (9y+6)(9y-6), using the difference of two squares formula

Answer 2

a² -b² = (a - b)(a + b)      

~~~~~~~~~~  

81x² - 36 = 9(9x² - 4) = 9(3x - 2)(3x + 2)