David W. answered 01/14/16
Experienced Prof
First, read and re-read the problem until you understand it and can put it into your own words. How's this: "If you have 33 coins in nickels and dimes that total $2.35. how many of each coin do you have?"
Assign variables.
Let n = number of nickels
Let d = number of dimes
Translate:
"Anna has $2.35 in nickels and dimes" means 5*n + 10*d = 235
[note: I find it easier to do all calculations in cents, then convert answer]
[also note: (number of coins)*(value of each coin) = (value of all coins]
"she has thirty three coins in all " means n + d = 33
"how many of each do you have?" means report n and d
Now, the easy math:
Solve for either n or d (let's solve for n) in the second equation:
n = 33 - d
Substitute for n in the first equation:
5*(33 - d) + 10*d = 235 [this gives and equation with only d]
165 - 5d + 10d = 235 [distribute]
5d = 70 [collect terms; subtract 165 from both sides]
d = 14 [divide both sides by 5]
Now, substitute that value into the other equation.
n = 33 - 14
n = 19
Checking (very important):
Is 5*(19) + 10*(14) = 235 ?
95 + 140 = 235 ?
235 = 235 ? yes
Is 19 + 14 = 33 ?
33 = 33 ? yes
Very humble p.s., I often make typos and mis-reads, so I am not at all surprised that other tutors have posted different answers. That is to be expected. The real value is in checking the work -- just like a spelling-check program finds my typos (usually), others find my math errors and I'm thankful. I still value the person, their knowledge, and their contribution to a better product; it is not good to belittle a person for making a mistake (we ALL make errors). Now, here is one of my best quotes: "With good people, a better process generally produces a better product."
See if you can find the error each other tutor made!