
Derek F. answered 01/13/16
Tutor
4.9
(8)
An excellent tutor must be clear, concise and patient.
1/sin(x) = csc(x)
cot(x) / cos(x) = cos(x)/sin(x) / cos(x) = 1/sin(x) = csc(x)
cot(x) / cos(x) +1/sin(x) = 2csc(x)