Hmm... Something is written a bit funny here...
Do you mean: 3x-2y =1 and 2y=x-1 ?
If so, then you would solve it like this:
We know what 2y equals because the second equation says 2y=x-1
So, we substitute that into the first equation. 3x - (x-1) =1. When we combine like terms we get: 2x +1 =1
We subtract 1 from both sides and get 2x=0
So, x=0. Then, we plug that back into the original equation to get y
0 - 2y = 1
y=-1/2
The solution is x=0 and y= -1/2
