Find the greatest possible pair of integers such that one integer is 4 less than twice the other and their sum is at most 50

Question

Algebra 1. Just solve please(:

Answer 1

Let the first of a pair of integers be “X”.

Then the second integer would be “2X - 4”

When you add two integers together the sum is an integer. If the sum of the above two variables is at the most 50, then the sum of the two variables needs to be exactly 50 (as opposed to 49, 48, 47 etc.). Therefore, I have the following equation:

X + 2X - 4 = 50

Combining like terms I get:

3X - 4 =50

Adding 4 to both sides of the equation I get:

3X = 54

To isolate the variable on one side of the equation, divide both sides of equation by 3 and get:

X = 18

If X = 18 , then the other value in the pair becomes

2X - 4 or:

2(18) - 4 =32

So the answer is (18, 32)

And 18 + 32 =50

Answer 2

 

the integers are x and 2x-4

x+2x-4<50

3x-4<50

3x<54

x=18

2x-4=2(18)-4

36-4=32

18 and 32 are the integers