Michael J. answered 01/07/16
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I will do the first one for you.
x + y = 3 eq1
x = 3y - 5 eq2
We can substitute eq2 into eq1, since eq2 is already defined by x.
3y - 5 + y = 3
Solve for y.
4y = 8
y = 2
Substitute this value of y into eq2 to solve for x.
x = 3(2) - 5
x = 6 - 5
x = 1
To solve graphically, we rearrange both equations so that they are in the y=mx+b form.
y = -x + 3 eq1
x + 5 = 3y ----> y = (1/3)x + (5/3) eq2
Graph both lines on the same coordinate system. To do this, plot the first point using the y-intercept and plot the second point using the slope. Then connect the two points for each in a straight line. You should have two lines.
For eq1, the two points will be (0, 3) and (1, 2). Connect these points throughout the entire coordinate system.
For eq2, the two points will be (0, 5/3) and (3, 8/5). Connect these points throughout the entire coordinate system.
Now that you have your lines, look for the point of intersection. The point of intersection should be (1, 2).