First of all, I believe there's a typo in your question. I'm going to assume the two equations are
A 9x + 5y = -16
B 2x - 10y = -48
I've prefaced the two equations with an A and a B so I can reference them easily.
To use the elimination method we need to make coefficient of one variable in the equation A equal to the negative of the coefficient of that same variable in equation B.
Looking at the two equations, I see 5y and -10y, so let's work with them
C 2(9x + 5y = -16)
and distributing
C 18x + 10y = -32
Let's use equation C (which is equation A times 2) and equation B.
C 18x + 10y = -32
B 2x - 10y = -48
If we add these two equations together, the y variable will be eliminated.
Adding them, we get
20x = -80
Dividing both sides by 20
x = -4
With this value of x, we can use either equation A, B or C to solve for y. I'll use equation B
2(-4) - 10y = -48
-8 - 10y = -48
-10y = -40
y = 4
So with x = -4 and y=4, the correct ordered pair is (-4,4) and the answer is D.
