Math Problem

Question

Suppose f(12)=-4. Determine a point which must lie on the graph of the following : y=-3f(x+8)-5, y=1/2f(4/3x)

Answer 1

If f(12) = 4, then we will use x=4 for the first graph. When we substitute x for 4, we get y = 3f(12) - 5 = 3*4-5 = 12-5 = 7. Therefore, the point (4,7) exists on the graph of y = 3f(x+8) - 5

 

For the second graph, we would substitute x for 1/9. Then we would get:

 

y = 1/2 * f(12) = 1/2 * 4 = 2

 

Therefore, the point (1/9, 2) exists on the graph of y= 1/2 * f(4/3x)