
Bruce Y. answered 12/12/15
Tutor
5
(9)
Experienced teacher and tutor, specializing in math
Since it's difficult to write the notation here, I'm guessing that you mean the second partial derivative of f, first with respect to y, then with respect to x. That's a two-step process.
To find the partial derivative wrt y, we treat x as if it were a constant, and differentiate wrt y:
fy(x,y) = 3x + 0 - 15y2
Let's see why, before we move on. Since x is treated as a constant, 3x is the coefficient of y. The derivative of a coefficient times y is just the coefficient, which is 3x.
Since x2 is being treated as a constant, its derivative is 0.
I'm sure you understand the 15y2 without any explanation.
So, fy(x,y) = 3x - 15y2
Now we take the partial derivative of this wrt x. Remember that we are now treating y as a constant, so 15y2 is a constant whose derivative is 0.
fyx(x,y) = 3 - 0 = 3. That's the answer.