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Question

A lot is in the shape of a right angle triangle. The shorter leg measures 90 m. The hypotenuse is 30 m longer than the length of the longer leg. How long is the longer leg?

Answer 1

Cool so we let the length of the longer leg be x

 

the hypotenuse would be (X+30) as given in the problem itself.

 

Now we are going to use Pythagoras's theorem

 

c^2 = a^2 + b^2

 

(X+30)^2 = 90^2 +  X ^2

 

x^2 + 60x + 900 = 8100 + x^2

 

60x = 8100 -900

 

60x = 7200

 

x = 120m

 

thus our longer leg is 120 m

Answer 2

Hi Peak, 

Step One: Remember the Pythagorean Theorem: a²+b²=c² where

a=shorter leg

b=longer leg

c=hypotenuse

Step Two: Plug in our values to the Pythagorean Theorem 

a²+b²=c²

a²+90²=(30+x)²

x²+8100=(30+x)(30+x)

x²+8100=900+60x+x²

x²-x²-60x+8100-900=0

-60x=-7200

x=120m

Best, 

Star