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(Yx2)+8=Y+12

How do you do this equasion

3 Answers by Expert Tutors

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Jason K. | Passionate Educator/ History NerdPassionate Educator/ History Nerd
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I would start by simplifying:

1. 2 times Y simply becomes 2Y.

2. So we are left with: 2Y+ 8 = Y + 12

-now we want to get the variable Y by itself on the left side of the equal sign, and our normal numbers combined on the right side.

3. subtract the 1Y on the right from both sides and you should get: Y+8=12.

4. now get the numbers over to the right side.  Since 8 is being added to the Y we must get rid of it by subtracting 8 from both sides.  You should get: Y=4.  

and thats it!

Uma L. | Math and Entrance Exam TutorMath and Entrance Exam Tutor
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(Yx2)+8=Y+12

2Y + 8 = Y + 12

Subtract  Y from boths sides

2Y -Y + 8 = - Y + 12

Y + 8 = 12

Subtract 8 form both sides

Y + 8 -8 = 12 - 8

Y = 4

 

 

Arthur S. | Math, Science, Chemistry, and Computer TutorMath, Science, Chemistry, and Computer T...
0

Jes,

(Yx2) equivalent to 2Y

so 2Y +8 = Y +12

now subtracting Y from each side gives

Y+8 = 12

subtracting 8 from each side gives

Y=4

Plug it back in

(4x2) +8 = 4 +12

8 +8 = 4 +12

16 =16 whxih checks

Hope that helps!

Art