(Yx2)+8=Y+12

Question

How do you do this equasion

Answer 1

I would start by simplifying:

1. 2 times Y simply becomes 2Y.

2. So we are left with: 2Y+ 8 = Y + 12

-now we want to get the variable Y by itself on the left side of the equal sign, and our normal numbers combined on the right side.

3. subtract the 1Y on the right from both sides and you should get: Y+8=12.

4. now get the numbers over to the right side.  Since 8 is being added to the Y we must get rid of it by subtracting 8 from both sides.  You should get: Y=4.  

and thats it!

Answer 2

(Yx2)+8=Y+12

2Y + 8 = Y + 12

Subtract  Y from boths sides

2Y -Y + 8 = Y  - Y + 12

Y + 8 = 12

Subtract 8 form both sides

Y + 8 -8 = 12 - 8

Y = 4

 

 

Answer 3

Jes,

(Yx2) equivalent to 2Y

so 2Y +8 = Y +12

now subtracting Y from each side gives

Y+8 = 12

subtracting 8 from each side gives

Y=4

Plug it back in

(4x2) +8 = 4 +12

8 +8 = 4 +12

16 =16 whxih checks

Hope that helps!

Art