Inactive Tutor answered 12/07/15
Tutor
New to Wyzant
A progression can generally be expressed as follows.
pk = s + (k-1)·c, k = 1, 2, 3, ...
where s and c are an integer 0 ≤ s ≤ 10, 1 ≤ c ≤ 10.
As a perfect square ends with any of 0, 1, 4, 5, 6, or 9,
a number which ends with any of 2, 3, 7, or 8 can not be a perfect square.
So, a combination (seed, constant) = (3, 10), for example, will produce a progression with no perfect square.
And, a progression with exactly one perfect square can not occur.
Hope these help.
Inactive Tutor
We have many progressions with multiple occurrence of perfect squares, where pairs of seeds and constants, (seed, constant), include (0, 10), (1, 10), (4, 10), (5, 10), (6, 10), and (9, 10). But, there is no progression with only a single perfect square. So, the answer to 3 above is "it can not occur".
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12/08/15
Pearl G.
-1.3t^2+41.6t+3
what hat is the maximum point of this?
How long does it take to hit the water ?
how fast is he going when he hits the water?
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12/16/15
Pearl G.
12/07/15