
Mehedi H. answered 05/04/16
Tutor
New to Wyzant
Mathematics, Physics and Physical Chemistry
Let, height of the tower = h m
side of the square base = 22*(h-3) m
height of the building = 9*h m
Therefore,
{22*(h-3)}2*9*h=235224
=> 9*h3-54*h2+81*h-486=0
=>(h-6)*(9*h2+81)=0
=> h=6; as (9*h2+81) cannot be zero.
So, radio tower is 6 m tall.
building is 54 m tall and side of the square base is 66 m.