Inactive Tutor answered 10/22/13
Tutor
New to Wyzant
loga b − loga c = loga (b / c)
loga x = b -----> ab = x
~~~~~~~~~~~
log2 x2 − log2 (x + 5) = 2
log2 [x2 / (x + 5)] = 2
x2
-------- = 22
x + 5
x2 = 4(x + 5)
x2 - 4x - 20 = 0
D = (-4)2 +80 = 96
x12 = (4 ± √96) / 2
x1 = 2 + 2√6 > 0
x2 = 2 − 2√6 < 0 (logarithm is not exist for negative numbers and 0)
x = 2(1 + √6) is the answer.
loga x = b -----> ab = x
~~~~~~~~~~~
log2 x2 − log2 (x + 5) = 2
log2 [x2 / (x + 5)] = 2
x2
-------- = 22
x + 5
x2 = 4(x + 5)
x2 - 4x - 20 = 0
D = (-4)2 +80 = 96
x12 = (4 ± √96) / 2
x1 = 2 + 2√6 > 0
x2 = 2 − 2√6 < 0 (logarithm is not exist for negative numbers and 0)
x = 2(1 + √6) is the answer.