Inactive Tutor answered 10/22/13
Tutor
New to Wyzant
loga b + loga c = loga bc
If loga b = loga c , then b = c
~~~~~~~~~~~
log4 x + log4 (x + 2) = log4 3
log4 x(x + 2) = log4 3
x(x + 2) = 3
x2 + 2x - 3 = 0
(x -1)(x + 3) = 0
x1 = 1
x2 = - 3 (The log function is only defined for positive values of the argument)
Thus, x = 1 is the answer.
If loga b = loga c , then b = c
~~~~~~~~~~~
log4 x + log4 (x + 2) = log4 3
log4 x(x + 2) = log4 3
x(x + 2) = 3
x2 + 2x - 3 = 0
(x -1)(x + 3) = 0
x1 = 1
x2 = - 3 (The log function is only defined for positive values of the argument)
Thus, x = 1 is the answer.