Assuming that the area, length times width = x4+10x2+9=(x2+9)(x2+1) and assuming that one of these factors is the height and the other the width, and that the width is the larger number, then it is x2+9 which is, for any real number greater than x2+1
Bailey H.
asked 11/29/15the area of a rectangle is x^4+10x^2+9. what is its width
this is for my algebra 2 online class. i'm a freshman in college so its a college level class (obviously) but i cant find where to figure this particular question out?? help!!!
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