Neal T. answered 11/29/15
Tutor
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Math!
Jim,
Here's one approach... given that the two circles are tangent and the distance between their respective centers is 7 yards, then: r1 + r2 = 7. Then, given that their combined areas equal 29π, (r1)2π + (r2)2π = 29π.
So let's solve for r1. Since, (r1)2π + (r2)2π = 29π, let's first get rid of π by dividing it out across the entire equation to give: (r1)2 + (r2)2 = 29. Next, since r1 + r2 = 7, r2 = 7 - r1 so let's substitute 7 - r1 for r2.
Now, we have:
(r1)2 + (7 - r1)2 = 29 FOIL the (7 - r1)2
(r1)2 + 49 - 14r1 + (r1)2 = 29 Rearrange and consolidate like terms: (r1)2 + (r1)2
2r12 - 14r1 + 49 = 29 Subtract 29 from both sides to try and factor
2r12 - 14r1 + 20 = 0 (2r1 - 10)(r1 - 2) = 0
So, r1 = 5 or r1 = 2 Both are viable radii lengths, so try substituting both into r1 + r2 = 7
5 + r2 = 7, therefore r2 = 2, or 2 + r2 = 7, therefore r2 = 5
Notice that they are interchangeable, so one radius is length 2 yards and the other radius is length 5 yards.
Hope this helps!