
David W. answered 11/22/15
Tutor
4.7
(90)
retired
You are on the right track; just keep thinking:
n f(n) Σ difference ratio
0 1 1
1 5 6 5-1=4 5/1=5
2 14 20 14-5 = 9 14/5=2.8
3 30 50 30-14 = 16 30/16 = 1.875
4 55 105 55-39 = 25 55/30 = 1.833
0 1 1
1 5 6 5-1=4 5/1=5
2 14 20 14-5 = 9 14/5=2.8
3 30 50 30-14 = 16 30/16 = 1.875
4 55 105 55-39 = 25 55/30 = 1.833
Since there is not a common difference between terms, it is not an Arithmetic Sequence.
Since there is not a common ratio between terms, it is not a Geometric Sequence.
There does, however, seem to be a pattern when we compute the differences between terms
[looks like the difference between term (n) and term (n-1) is the square of [n+1)],
so, an = (n+1)2 + an-1 for n>0
an= 1 for n=0
[note: this is the recursive definition of the series.]
Each f(n) is the sum of the squares of the numbers from 1 (or from 0) to (n+1). For example, f(4) = 12 + 22 + 32 + 42 +52= 1 + 4 + 9 + 16 + 25 = 55.
A formula for the sum of squares can be derived in different ways (depending on your level of math). See:
http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalSquares.htm
It is written as: f(n) = (n/6)(n+1)(2n+1).
Be sure to replace this n with the (n+1) in this problem (for example our f(4) is the sum of squares of numbers 0 to 5):
f(n) = ((n+1)/6)(n+2)(2n+3)
and, for example, f(4) = (5/6)(6)(11) = 55
Yasmine S.
11/22/15