Philip P. answered 04/26/14
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Here it is for k=1 (vice k=11) to k=5:
5
∑ (1/2)k = (1/2)(1) + (1/2)(2) + (1/2)(3) + (1/2)(4) + (1/2)(5)
k=1
∑ (1/2)k = (1/2)(1) + (1/2)(2) + (1/2)(3) + (1/2)(4) + (1/2)(5)
k=1
= (1/2) + 1 + (3/2) + 2 + (5/2) = ?