Rabia O. answered 11/17/15
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Tutor with extensive knoweldge in Engineering and Math
solve equations 1 and 3 by multiplying equation 3 by 2 and subtract the the result from equation 1
(2x-2x)+(2y-(-y))+(2z-(-2z))=-3(2)-(-5)
3y+4z=-1
solving the result equation with equation 2 by subtracting the equation from equation 2
5z=-5 --------> z=-1
substitution in equation 2
3y-(-1)=4 ------> 3y=4-1 ----->y=1
substitution in equation 3
x+1+(-1)=-3 -------> x=-3
the solution is x=-3, y=1, z=-1