You are correct that F1 (6,-2) is one point, simply a reflection over
the y-axis. Now consider the line drawn connecting points D and
E as a side of ΔDEF. You will want to reflect your found point
the y-axis. Now consider the line drawn connecting points D and
E as a side of ΔDEF. You will want to reflect your found point
F1 (6,-2) over this line to find point F2, the second point.
Find the equation of the line drawn thru points D and E (y=(4/3)x-(1/3))
Find the equation of the line drawn thru points D and E (y=(4/3)x-(1/3))
Find the equation of the line perpendicular to this line passing thru
F1 (y=(-3/4)x+(10/4)). Second point, F2 (-3.28,4.96), will lie on this
line the same distance from DE as F1. Verify above equations and
coordinates.
This should guide you toward your solution, now show the work.