Michael J. answered 11/08/15
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2x + 3y = 20 eq1
-10x + 5y = 20 eq2
Multiply eq1 by -5 so that both equations have the same coefficient of x.
-10x - 15y = -100 new eq1
-10x + 5y = 20 eq2
Subtract eq2 from new eq1 to eliminate the x terms.
-20y = -120
Divide both sides of the equation by -20.
y = 6
Substitute this value of y into eq1 to solve for x.
2x + 3(6) = 20
2x + 18 = 20
2x = 2
x = 1
Your solution is (1, 6).