(a5b0)3/(2ba3)=

Question

please help me!!!

 

Answer 1

Correct, otherwise it would be:

 

(a5b0)3

---------

(2ba3)

 

multiplication by 0 in the numerator would make it:

 

0

----

6ba

 

and 0 divided by any number (other than 0) is 0:

 

0

Answer 2

I'm going to assume the equation you wrote is this:

 

(a⁵•b⁰)³

---------   =  ?

(2b•a³)

 

The "cube" on the numerator's parentheses means 

 

a5•b0 • a5•b0 • a5•b0 

 

 

Since multiplying numbers means adding the exponents of the like terms, then

 

a^(5+5+5)•b^(0+0+0)  =  a¹⁵•b⁰

 

 

Thus you have

 

a¹⁵•b⁰

--------  = ?

2b•a³

 

 

The zero exponent means "1", therefore

 

a¹⁵•1
-------- = ?
2b•a³

 

 

Multiplication is commutative, so you can rearrange the denominator

 

a¹⁵•1
-------- = ?
a³•2b

 

 

And you can combine like terms into separate fractions, like this

 

a¹⁵     1
---- • ---- = ?
a³      2b

 

 

Dividing numbers means subtracting the exponents of the denominator from the exponents of the numerator, so

 

a^(15-3) = a¹²

 

and

 

a¹²      1
---- • ---- = ?
  1      2b

 

Recombining results in

 

 a¹² 

------ = ?
  2b

 

 

So the answer is 

 

(a⁵•b⁰)³     a¹² 
--------- =  -----
(2b•a³)       2b

 

Of course, this is all assuming my interpretation of your problem is correct. Even if it's not, the principles shown here still hold.

 

Hope this helps!