
Tamara J. answered 11/02/12
Math Tutoring - Algebra and Calculus (all levels)
You can also use the method of elimination.
First, move all the terms with variables to one side of the equation.
y = x - 8 ==> y - x = x - 8 - x ==> y - x = -8
y = 5x ==> y - 5x = 5x - 5x ==> y - 5x = 0
Now, you want to add these two equations in a way that will eliminate one of the variables, which would leave you with the other variable to solve for.
So, (1) y - x = -8
(2) y - 5x = 0
Multiplying equation (2) by a -1 will give you a -y, which will be eliminated when added to equation (1).
That is:
(2) -1 * ( y - 5x = 0) ==> (-1)*y - (-1)*5x = (-1)*0 ==> -y - (-5x) = 0
==> -y + 5x = 0
Add this new equation to equation (1) above.
(1) y - x = -8
(2) -y + 5x = 0
+______________
0y + 4x = -8
4x = -8
(4x)/4 = (-8)/4
x = -2
Now that you have found x, plug into one of the original equations to find y.
(1) y = x - 8 ==> y = (-2) - 8 = -10
(2) y = 5x ==> y = 5*(-2) = -10
Thus, the solution for this system of equations is (-2, -10). You can check the answer by graphing these two linear equations on the same x,y-graph and finding the point at which they intersect, which should be (-2, -10).