What is (2+y)^3 written out? Now take that equation, what is dy/dx?

Question

(2+y)³ (written out)

 

Now what is dy/dx?

Answer 1

After distributing the exponents, you should have Y^3+6Y^2+12Y+8

 

Now to find dy/dx of an implicit function (and I call it an implicit function because there is really no X present within the function)

 

So, d(Y^3+6Y^2+12Y+8)/dx= 3y^2(dy/dx)+6Y(dy/dx)+ 12