How high is the highest point of the trajectory?

Question

answer in units of m. (Part two to my last question on the cannon).

Answer 1

Maximum height h = v_y² / 2g 

v_y = v sinθ =148.8 sin 22 = 55.7 m/s

 

h= 55.7² / 2(9.8)

 

h= 158.3 m