What is the magnitude of the initial velocity?

Question

a cannon sends a projectile towards a target a distance 1570m away. The initial velocity makes an angle 22 degrees With the horizontal. The target is hit. Acceleration of gravity is 9.8m/s2 And answer in units of m/s.

Answer 1

θ=22^{°,   R=1570 m g=9.8 m/s2  , initial velocity = v} 

 

v = ((R g)/sin2θ)^1/2

 

v = ((1570 x 9.8)/sin 44)^1/2

 

v = 148.8 m/s