Find its horizontal range

Question

(this is part two to the last question I asked about the artillery shell). 

Answer 1

Horizontal range R=(v² sin 2θ)/g, θ=62.9° and 2θ=2(62.9)=125.8°

R=(168² sin62.9)/9.8, sin 2θ = 0.81

 

R= (28224)(0.81)/9.8

R = 2332.8 m