If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?

Question

HELP ME PLEASE :( .................

Answer 1

Hi Ari;

I do not know your background.  I am therefore going to assume you are unfamiliar with

y=mx+b

 

m=slope

b=y-intercept

 

It is a given fact that the line crosses the y-axis at (0,1)...

b=1

Therefore...

y=mx+1

 

It is a given fact that the slope of the line is 4/5...

m=4/5

Therefore...

y=((4/5)(x))+1

Answer 2

y = mx + b

 

m = 4/5, 

 

the point (0, 1) is the y-intercept, so b = 1

 

 

so,

 

y = (4/5)x + 1