What is h'(0)? and What is j'(1)?

Question

Let h(x)=g(x)sin x and j(x)=[f(x)+x^2]^3

If g(0)=9, g'(0)=-3, f'(1)=2

Answer 1

h'(x)= g(x)*cosx + sin x*g'(x)

plug in 0 for x

h'(0)=g(0)*cos0 +sin 0*g'(0)

 

h'(0)=9*1+0*9=9

 

j'(x)=3[f(x)+x²]²*(f'(x)+2x)

Plug in 1 for x and get

 

YOU DIDN't INCLUDE WHAT F(1) is equal to....so I can't finish it