Find two positive integers whose sum is 48, and whose sum also equals twice their difference.

Question

 Find two positive integers whose sum is 48, and whose sum also equals twice their difference.

Answer 1

x+y=48

x=48-y

 

48= 2(x-y)

48=2(48-y-y)

48=2(48-2y)

48= 96-4y

-48=-4y

12=y

 

x+12=48

x=36

 

(36, 12)