1. √(2x+5) - 3 = √(x-2)
Square both sides: 2x+5 - 6√(2x+5) + 9 = x-2
Isolate the remaining radical term: -6√(2x+5) = -16-x
Square both sides and simplify: 36(2x+5) = 256+32x+x2
72x + 180 = 256 + 32x + x2
x2 - 40x + 76 = 0
(x-38)(x-2) = 0
x = 38 or x = 2
Substitute each value into the ORIGINAL equation. They both satisfy the equation, so the solutions are 38 and 2.
2. c(t) = √t
c(200) = √200 = √100√2 = 10√2