2x^2 +14x =88

The solution or solutions is (are) x=?

2x^2 +14x =88

The solution or solutions is (are) x=?

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Blacksburg, VA

Hey Brandon -- cut in half 2x^2 +14x =88 ... x^2 +7x -44 =0 ... try -4x11 to get +7

(x+11)(x-4) =0 ... x= -11 or 4 Regards, sir :)

Saugus, MA

2x^2+14x=88

subtract 88 from both sides

2x^2+14x-88=0

divide both sides of the equation by 2 to get x^2+7x-44=0

the equation is in the form ax^2+bx+c=0

a and b are both odd, (1 and 7)

therefore c(-44) must be factored into an odd number times an even number, NOT an even times an even

therefore you can't use 2 and 22, you must use 1 and 44 or 4 and 11(disregarding signs for the moment)

does adding 11 and 4 or subtracting 11 and 4 give you 7 ? YES, 11-4=7

-44=(4)(-11) or (-4)(11)

the coefficient of x must be +7, so you can't use 4 and -11(-11+4=-7)

you must use -4 and 11 because 11+(-4)=7

therefore you get 2(x+11)(x-4)=0

x+11=0 and x-4=0

x=-11 and x=4

Willowbrook, IL

First, divide both side by 2. You will get:

x^{2}+7x=44 or

x^{2}+7x-44=0;

You may use factoring. Two factors that multiply to get -44 are -11 and 4. Their sum shall be equal to coefficient in front of x, but with opposite sign. Indeed, -11+4=-7, just as it should be.

So the trinomial can be factored as follows:

x^{2}+7x-44=(x+11)(x-4); If (x+11)(x-4)=0 then **x=-11 or x=4**.

Braintree, MA

2x^2 +14x =88

2x^2 +14x - 88 = 0

2(x^2 +7x - 44) = 0

2(x + 11)(x - 4) = 0

x = -11 or x = 4

Hyattsville, MD

1. First subtract 88 from both sides so that the equation is equal to 0.

2x^{2} +14x - 88 = 0

2. Find the Highest Common Factor (HCF) that can be divided into each term

in the trinomial.

3. Factor the remaining trinomial.

2 (x^{2} +7x - 44) = 0

a. Find the pairs of factors of the third term -44 = **-4,11** or 4, -11;

-2,22 or 2, -22; -1,44, 1,-44;

b. Choose the pair of factors that when added together give +7,

the coefficient of the middle term. These are **-4** and
**+11**.

4. Finally use the zero product property to solve the equation.

x - 4 = 0 | x + 11 = 0

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