I need help finding the vertex of this parabola

Question

f(x) = x^2 -10x - 7

Answer 1

 Generally Speaking:

   

   In equation Y = aX²  + bx + c

 

      Vertex ( - b/ 2a, f ( -b/2a) )

 

         f( -b/2a) = ( b²  - 4ac) / 4a²

Answer 2

Hi Harry,

The equation you have is in standard form (y = ax^2 + bx + c), so we can use the formula -b/(2a) to find the x-coordinate of the vertex.

x = -(-10)/(2*1)

x = 5

 

Now plug 5 into your equation to solve for the y-coordinate of the vertex.

y = 5^2 - 10(5) -7

y = 25 - 50 - 7

y = -32

 

Your vertex is at (5, -32).

 

Let me know if this helps!